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=512-0.5Y^2
We move all terms to the left:
-(512-0.5Y^2)=0
We get rid of parentheses
0.5Y^2-512=0
a = 0.5; b = 0; c = -512;
Δ = b2-4ac
Δ = 02-4·0.5·(-512)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*0.5}=\frac{-32}{1} =-32 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*0.5}=\frac{32}{1} =32 $
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